Ques 4: Can we use time shifting to simplify signal operations?

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The discussion revolves around using time shifting to simplify signal operations, specifically with the signal x[n]. There are questions regarding the correct transformations for x[4-n] and x[2n], with confusion about the expected outputs. Participants debate the implications of time shifting and scaling on the signal, particularly how to handle the unit step function in calculations like x[n]u[2-n]. There is also concern about the removal of an answer by a participant, raising questions about its correctness. The conversation highlights the complexities of signal manipulation and the need for clarity in solutions.
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Kindly see the question above.

First signal is x[n]

Ques 1: we are required to find x[4-n]

The way I did, the answer should be (a) but one of the solution says (b).

Which is the correct one?Ques 2: What are we to do while finding x[2n]? Consider only 0, 1 and 2 as twice of those gives 0, 2 and 4 which is what we have from x[n]? or does the whole signal redistribute at -2, 0, 2,4, 6, 8?

Ques 3: How do we calculate x[n]u[2-n]?
I took unit step signal, flipped it at 0 to get u[-n] and then shifted it by 2 which makes the new step signal from -2 to - infinity. Multiplying this with x[n] gives zero. Is it correct?
 
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@salzrah Why did you remove the answer? is it wrong or what?
 

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