Question about a differentail equation

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The discussion centers on solving a differential equation related to speed in an electromagnetism context. The user derived the formula dv/v = ((B2L2)/(Rm))dt and integrated it to obtain v = e^((B2L2)/(Rm))T. However, they noted the absence of an initial velocity term (Vo) in their solution. A participant clarified that the constant of integration was overlooked, leading to the correct expression ln|v| = ((B2L2)/(Rm))t + C, which includes the initial condition.

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Homework Statement


...what is speed at a later time T. It a physics problem(electromagnetism)

Homework Equations





The Attempt at a Solution


ok so i got up to this formula
dv/v=((B2L2)/(Rm))dt
and i do the integration and get
v=e((B2L2)/(Rm))T but the answer is similar but has a Vo before the e. Whats with the Vo?
thanks
 
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leonne said:

Homework Statement


...what is speed at a later time T. It a physics problem(electromagnetism)

Homework Equations





The Attempt at a Solution


ok so i got up to this formula
dv/v=((B2L2)/(Rm))dt
and i do the integration and get
v=e((B2L2)/(Rm))T but the answer is similar but has a Vo before the e. Whats with the Vo?
thanks
It looks like you forgot the constant of integration.

From this equation,
dv/v=((B2L2)/(Rm))dt

you get ln|v| = ((B2L2)/(Rm))t + C
 
o yeah ok thanks
 

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