Question about Full scale deflection

In summary: You need to use Ohm's law, and solve for the current. Lets do it:120 V = (90 kOhms)( .001 A) = 9.9 VWith the right units, this equation is useful.
  • #1
Tony Meloni
6
0

Homework Statement


hello, just came across this type of question for first time.
A voltmeter with a range of 0-30volts is to be used to measure a 120 volt circuit. calculate the value of the resistor to be placed in series with the meter. the sensitivity of the meter is 1000 ohms per volt ?

Homework Equations



im taking a guess its 120-30 = 90 vd x 1000 = 90k ohms ? any input would help thanks

The Attempt at a Solution

 
Physics news on Phys.org
  • #2
Don't guess. What does the sensitivity tell you about the resistance at 30 V at the voltmeter?
 
  • #3
its telling me at 30volts its 30k ohms since its 1k per volt ..needs 90volts to drop across the resistor .. 120volt x 1000 k = 120k - 30k = 90k x .001ma = 90vd ?
 
Last edited:
  • #4
Tony Meloni said:
120volt x 1000 k
What do you multiply here and what are the units? k without a unit doesn't have a proper meaning.
Tony Meloni said:
120volt x 1000 k = 120k - 30k
That equation is wrong.
Tony Meloni said:
120k - 30k = 90k x .001ma
That equation is wrong as well.
Tony Meloni said:
90k x .001ma = 90vd
That equation has at least an issue with units.
 
  • #5
so what are the proper steps to find the answer ?
 
  • #6
If the voltmeter has 30 kOhm, what is the maximal current flowing through it?

At this current, what do you need as additional resistance to get 90 V voltage drop there?
 
  • #7
my choices to pick from the homework are

60k ohms 90k ohms

90ohms 150k ohms

if you take 90k x .001 you get 90vd
 
  • #8
Tony Meloni said:
if you take 90k x .001 you get 90vd
With the right units this can be useful.

Work with units. It helps spotting most errors you'll make if you don't work with them.
 
  • #9
what do you mean by units ?
 
  • #11
how would you write out the problem using ohms law ?
 
  • #12
That's your homework task. You need a few simple steps in a row, going from the voltmeter to the additional resistor step by step.
 

1. What is full scale deflection?

Full scale deflection refers to the maximum value displayed on a measuring instrument or the maximum range of a measurement. It is the point at which the instrument or measurement is at its highest value and cannot be further increased.

2. How is full scale deflection determined?

Full scale deflection is determined by the sensitivity of the measuring instrument and the range it is designed to measure. The sensitivity is the smallest change in value that the instrument can detect, and the range is the maximum value it can display.

3. What is the purpose of full scale deflection?

The purpose of full scale deflection is to provide a reference point for measurements and to ensure that the instrument is functioning correctly. It also allows for easy comparison between different measurements and instruments.

4. Can full scale deflection be adjusted?

In some cases, full scale deflection can be adjusted by changing the sensitivity or range of the instrument. However, this should only be done by trained professionals to ensure accurate and reliable measurements.

5. How is full scale deflection different from zero deflection?

Full scale deflection is the maximum value displayed on an instrument, while zero deflection is the minimum value displayed. Full scale deflection is the highest point of measurement, while zero deflection is the starting point.

Similar threads

  • Introductory Physics Homework Help
Replies
3
Views
526
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
18
Views
6K
  • Introductory Physics Homework Help
2
Replies
45
Views
3K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
923
  • Introductory Physics Homework Help
Replies
4
Views
999
  • Classical Physics
2
Replies
57
Views
7K
  • Introductory Physics Homework Help
Replies
4
Views
6K
  • Introductory Physics Homework Help
Replies
3
Views
1K
Back
Top