Question about Full scale deflection

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Homework Help Overview

The discussion revolves around a problem involving a voltmeter with a specified range and sensitivity, tasked with measuring a higher voltage circuit. The original poster seeks to determine the appropriate resistor value to be placed in series with the voltmeter to ensure accurate readings.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the implications of the voltmeter's sensitivity and how it relates to resistance. There are attempts to calculate the required resistance based on voltage drops and current, but some calculations are questioned for accuracy and unit consistency.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions and calculations. Some guidance has been offered regarding the importance of units in calculations, and there is a focus on clarifying the steps needed to approach the problem correctly.

Contextual Notes

The original poster is working within the constraints of a homework assignment, which includes specific resistor options to choose from. There is an emphasis on understanding the relationship between voltage, current, and resistance as per Ohm's law.

Tony Meloni
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Homework Statement


hello, just came across this type of question for first time.
A voltmeter with a range of 0-30volts is to be used to measure a 120 volt circuit. calculate the value of the resistor to be placed in series with the meter. the sensitivity of the meter is 1000 ohms per volt ?

Homework Equations



im taking a guess its 120-30 = 90 vd x 1000 = 90k ohms ? any input would help thanks

The Attempt at a Solution

 
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Don't guess. What does the sensitivity tell you about the resistance at 30 V at the voltmeter?
 
its telling me at 30volts its 30k ohms since its 1k per volt ..needs 90volts to drop across the resistor .. 120volt x 1000 k = 120k - 30k = 90k x .001ma = 90vd ?
 
Last edited:
Tony Meloni said:
120volt x 1000 k
What do you multiply here and what are the units? k without a unit doesn't have a proper meaning.
Tony Meloni said:
120volt x 1000 k = 120k - 30k
That equation is wrong.
Tony Meloni said:
120k - 30k = 90k x .001ma
That equation is wrong as well.
Tony Meloni said:
90k x .001ma = 90vd
That equation has at least an issue with units.
 
so what are the proper steps to find the answer ?
 
If the voltmeter has 30 kOhm, what is the maximal current flowing through it?

At this current, what do you need as additional resistance to get 90 V voltage drop there?
 
my choices to pick from the homework are

60k ohms 90k ohms

90ohms 150k ohms

if you take 90k x .001 you get 90vd
 
Tony Meloni said:
if you take 90k x .001 you get 90vd
With the right units this can be useful.

Work with units. It helps spotting most errors you'll make if you don't work with them.
 
what do you mean by units ?
 
  • #10
Ohm, Volt, Ampere and so on.
 
  • #11
how would you write out the problem using ohms law ?
 
  • #12
That's your homework task. You need a few simple steps in a row, going from the voltmeter to the additional resistor step by step.
 

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