- #1
mesa
Gold Member
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How would you graph a square of any dimension on the cartesian coordinate system?
Hey mesa.
What exactly do you mean? Do you mean instead of representing x you represent x2 for a particular vector (where x is the 1st element of the vector)?
Maybe mesa means an actual square (quadrilateral)?
Ohh I see what you're saying now.
It depends on the number of dimensions and the particular attribute you are trying to visualize.
Typically what happens in high-dimensional spaces, is that a specific kind of projection is used to create a visual of that attribute in a two or three dimensional space.
The short answer is that it depends on the attribute you are trying to visualize, but the kinds of things would most likely be similar if not equivalent to the ones used in a normal cartesian geometry. (It's hard to give specifics without specifics).
Basically I am looking for (an)other function(s) that will result in a graph of a plain old square on a two dimensional cartesian coordinate system.
##|x|+|y|=1##
##max \{ |x|,|y|\} = 1##
That's a nice solution, and takes care of the domain/range problems I was having.
Got anything else?
You can rotate and translate it to anywhere and resize it by changing the 1:$$
|(x-a)\cos(\alpha)-(y-b)\sin(\alpha)|+|(x-a)\sin(\alpha)+(y-b)\cos(\alpha)| = 1$$
Isn't there a problem at x=0 or am I missing something?[tex]|x+y|-|x-y| = 1[/tex]
[tex]|x+y|-|x-y| = 1[/tex]
Isn't there a problem at x=0 or am I missing something?
That's just a typo, he means ##|x+y|+|x-y|=1##. Same as my first one but squared up with the axes.