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Question about parameterizing curve of intersection.

  1. Jun 10, 2012 #1
    I couldn't find any resources in my book or online dedicated to this subject. I honestly don't even know where to begin for this problem.
    1. The problem statement, all variables and given/known data

    Let [itex] f(x,y) = 4 / (1+ x^2 + y^2) [/itex] and let S be the surface given by the graph of f(x,y)

    b) Let C2 denote the curve in the xy-plane given by [itex] r(t)= t, 3/2 − t^2[/itex] and let C denote the curve on the surface S which has C2 as its shadow in the xy-plane. Find the parametric equations r = r(t) for C


    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jun 10, 2012 #2
    how about the "graph" over the curve,

    [tex](r(t),f(r(t))=(x(t),y(t),z(x(t),y(t)))[/tex]

    Then it is a curve, on the surface, and it's shadow is r(t), correct?
     
    Last edited: Jun 10, 2012
  4. Jun 10, 2012 #3
    Hrmm.. I'm not too sure honestly. I think this all has to do with arc-length/curvature. If that is correct then I think I will go study more about that and see if I can't figure it out
     
    Last edited: Jun 10, 2012
  5. Jun 10, 2012 #4
    I would not discourage you from exploring the concepts, and so develop your understanding of the subject as a whole. However, I think you'll find, while my hint is somewhat abstract, it is more or less correct, and that curvature and arc-length do not apply here. But again, please do investigate and compare the concepts!

    Also, my use of the word graph is not a bad definition for you to understand, Stewart uses it in his textbook on calculus; here is the definition of graph (there are other definitions) on wikipeida:

    http://en.wikipedia.org/wiki/Graph_of_a_function

    In other words, what is the graph associated with the function (x,y) --> z=f(x,y)
     
  6. Jun 10, 2012 #5
    I dont deal well with this sort of abstraction.

    In my mind what you are saying is we can come up with a new function which is simply our old function r(t) plus a new variable which is the sum of the variables of our original function.

    Correct me if I am wrong.

    But it would appear to me that we need our original function to come up with the parameters, since S is the measure of the surface of [itex] f(x,y)=4/(1+x2+y2) [/itex].

    Oh and one last thing. A "shadow" is simply a projection correct?
     
  7. Jun 10, 2012 #6

    HallsofIvy

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    There is no abstraction here! You are given x and y in terms of t and told how to calculate z in terms of x and y. So what is z in terms of t? It is just basic algebra.
     
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