Question about reflectivity and maximization of energy reflected

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SUMMARY

The discussion focuses on maximizing the energy reflected from a pond's surface with an index of refraction of 9.0 using a linearly polarized microwave transmitter. The key conclusion is that to achieve maximum reflection, the dipole should be oriented perpendicular to the plane of incidence, ensuring the electric field is also perpendicular. The optimal incident angle for the wave is suggested to be approaching π/2 radians. Additionally, the concept of Brewster's angle is recommended for further study.

PREREQUISITES
  • Understanding of microwave transmission and polarization
  • Familiarity with the concepts of reflection coefficients, specifically $$r_{per}$$ and $$r_{par}$$
  • Knowledge of Snell's Law and its application in optics
  • Basic grasp of Brewster's angle and its significance in polarization
NEXT STEPS
  • Study the derivation and implications of Brewster's angle in optics
  • Explore the mathematical formulation of reflection coefficients for different polarizations
  • Investigate the effects of varying indices of refraction on wave reflection
  • Learn about practical applications of polarized microwaves in communication technologies
USEFUL FOR

This discussion is beneficial for physicists, electrical engineers, and anyone involved in microwave technology or optics, particularly those interested in enhancing energy reflection techniques.

LCSphysicist
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Homework Statement
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Imagine that we have a transmitter of microwaves that radiates a linearly polarized wave whose E field is known to be parallel to the dipole direction. We wish to reflect as much energy as possible off the surface of a pond (having an index of refraction of 9.0). Find the necessary incident angle and comment on the orientation of the beam.

I have solved it, but since the textbook has no solutions on it i would like to know if you agree with my answer:
Since for electric field perpendicular to the plane of incidence $$r_{per} = sin^2(\Delta \theta)/sin^2(\sum \theta)$$

And for electric field parallel $$r_{par} = tan^2(\Delta \theta)/tan^2(\sum \theta)$$

We have $$r_{par} = tan^2(\Delta \theta)/tan^2(\sum \theta) = r_{per} cos^2(\sum \theta)/cos^2(\Delta \theta) < r_{per} $$

So, since we want to maximize the reflected energy, we should make the dipole perpendicular to the plane of incidence.

The problem is about the angle of incidence. My answer would be something like:

"To got maximum reflection energy, make the dipole perpendicular to the plane of incidence, so that the electric field is also perpendicular to the plane. About the angle, make the incident angle of the wave ##\theta \to \pi/2##.

What do you think?
 
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