Question about the Heisenberg Picture

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SUMMARY

The discussion centers on the application of the Heisenberg equation of motion to the Simple Harmonic Oscillator (SHO). The participant questions the necessity of solving for the momentum operator when focusing solely on the position operator's time evolution. They also explore the common practice of solving the second-order differential equation derived from the equations of motion, rather than integrating the first-order equation directly. The equations discussed are \dot{x}(t) = \frac{p(t)}{m} and \dot{p}(t) = -m\omega^2x(t), emphasizing the interdependence of position and momentum in quantum mechanics.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically the Heisenberg picture.
  • Familiarity with differential equations, particularly second-order equations.
  • Knowledge of the Simple Harmonic Oscillator (SHO) model.
  • Basic grasp of operator algebra in quantum mechanics.
NEXT STEPS
  • Study the derivation and implications of the Heisenberg equation of motion.
  • Learn about the role of commutators in quantum mechanics, particularly in the Heisenberg picture.
  • Explore techniques for solving second-order differential equations in physics.
  • Investigate the relationship between position and momentum operators in quantum systems.
USEFUL FOR

Students and professionals in physics, particularly those focusing on quantum mechanics and the mathematical foundations of the Heisenberg picture. This discussion is beneficial for anyone looking to deepen their understanding of the dynamics of quantum systems.

Beer-monster
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Homework Statement



I've seen this example for using the Heisenberg equation of motion to solve the Simple Hamonic Oscillator.

http://en.wikipedia.org/wiki/Heisenberg_picture#Commutator_relations"

However, if you were only interested in one variable, let's say position, on how the the position operator varies in time and its resulting expectation values: Would is it necessary to find and solve the equation of motion for P as well?

Also once one has the relevant equation of potion:

[tex]\frac{dX(t)}{dt} = \frac{p(0)}{m}[/tex]

Why is it so often solved by differentiating the equation a second time and solving, rather than just integrating?



Homework Equations





The Attempt at a Solution


 
Last edited by a moderator:
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The equations for the SHO are
\begin{align*}
\dot{x}(t) &= \frac{p(t)}{m} \\
\dot{p}(t) &= -m\omega^2x(t)
\end{align*}Note that you have functions of time on both sides of the equations. You don't have p(0) on the right-hand side of the x equation. You differentiate one equation and substitute in the second one to get rid of one of the functions. The resulting second-order equation is straightforward to solve.
 
Thanks for the reply, Vela.

I was thinking about it earlier as I walked the dog, but hadn't got around to sitting down with it. I did wonder if assuming that the answer in the commutator was p(0) was unfounded.

Glad to have someone confirm it and that'd I'm not a complete idiot, just a bit slow :D
 

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