The maxwell's equations in vacuum are satisfied by a non trivial solution involving [tex]\vec E (t,\vec x)[/tex] and [tex]\vec B (t, \vec x)[/tex]. Correct me if I'm wrong.(adsbygoogle = window.adsbygoogle || []).push({});

I don't really understand the physical interpretation of the solution. I know that if I'm given an initial condition then I can know the solution for all t and [tex]\vec x[/tex]. Assuming I'm given an initial condition... then I'd have that a varying electromagnetic field satisfies the Maxwell's equations for all the space and at any time. Does this mean that vacuum doesn't contain any charge (pretty likely) and further is like a soup of electromagnetic waves (which is what strikes me)?

I mean, to my understanding, there's anon vanishing electromagnetic field in all the space at any time, all thisin vacuum. Am I understanding this well?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Question about the solution to Maxwell's equations in vacuum

**Physics Forums | Science Articles, Homework Help, Discussion**