I have a question about gauges in gravity.(adsbygoogle = window.adsbygoogle || []).push({});

Symmetric tensor field in four dimensions has 10 independet components, when we want to describe massless spin-two field (graviton) we impose harmonic gauge which reduces 10 independet components to 6 and afterwards we use diff invariance and eventually go down from 6 to 2 independet components. And all this happens with harmonic gauge.

++++++++++++++++++++++++++++++++++++++++

What is a transverse-traceless gauge?

Transverese means d_mu (h_mu_nu)=0 and this puts constraints on 4 components out of initial 10 components of symmetric tensor...

Traceless means Tr (h_mu_nu)=0 and this puts constraint on 1 component....

So TT gauge puts constraints 5 constraints on 10 components of symmetric tensor field.... and what to do next how to reduce to 2 components to describe graviton .... how do i cast TT gauge in the same sense as i did for harmonic gauge above... ?

Thank you

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Question about transverese-traceless gauge in gravity

**Physics Forums | Science Articles, Homework Help, Discussion**