Question About Work-Energy Theorem

AI Thread Summary
The Work-Kinetic Energy Theorem states that the work done on an object is equal to the change in its kinetic energy, expressed as W=ΔK. In problems involving multiple forces, it is valid to sum the work done by all forces, leading to the equation ∑W = ΔK. This aligns with Newton's second law, where the net force (F) acting on an object determines its acceleration (a). Consequently, the net work (W) done on the object corresponds to the change in kinetic energy. Understanding this relationship clarifies the application of the theorem in complex scenarios.
dlacombe13
Messages
100
Reaction score
3
Very simple question. So I am on a homework problem, and I want to make sure that I am using this theorem correctly. My book states that the Work-Kinetic Energy Theorem is:

W=ΔK

Now the solution to this problem involved multiple forces and thus each force is doing work. So my question is, is it legal to say that:

∑W = ΔK
 
Physics news on Phys.org
dlacombe13 said:
Very simple question. So I am on a homework problem, and I want to make sure that I am using this theorem correctly. My book states that the Work-Kinetic Energy Theorem is:

W=ΔK

Now the solution to this problem involved multiple forces and thus each force is doing work. So my question is, is it legal to say that:

∑W = ΔK

Yes. Precisely.
 
  • Like
Likes vanhees71 and dlacombe13
Thank you, the problem makes complete sense to me now!
 
In Newton's second law, F = ma, F is always the net force acting on an object. Therefore, in the work-energy theorem, W is always the net work done on the object.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Let there be a person in a not yet optimally designed sled at h meters in height. Let this sled free fall but user can steer by tilting their body weight in the sled or by optimal sled shape design point it in some horizontal direction where it is wanted to go - in any horizontal direction but once picked fixed. How to calculate horizontal distance d achievable as function of height h. Thus what is f(h) = d. Put another way, imagine a helicopter rises to a height h, but then shuts off all...
Back
Top