Question from reading Div Grad Curl and All That

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Discussion Overview

The discussion revolves around the derivation of the normal vector to a surface as presented in the book "Div Grad Curl and All That." Participants are examining the mathematical representation of a tangent vector on a surface intersected by a plane parallel to the xz plane, specifically focusing on the relationship between the components of the tangent vector and the partial derivatives of the surface function.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions why the component in the z direction is expressed as 'partial f/partial x times u sub x,' seeking clarification on the mathematical reasoning behind this representation.
  • Another participant challenges the initial claim by pointing out a potential misinterpretation regarding the direction of the vector components, suggesting that 'u sub z' cannot be represented as 'partial f/partial x times u sub x' if 'u sub x' is a vector in the x direction.
  • A later reply clarifies that 'f' refers to the 3-dimensional surface defined by z=f(x,y), and emphasizes the context of the 2-dimensional representation of the curve in the xz plane.

Areas of Agreement / Disagreement

Participants express differing views on the mathematical representation of the tangent vector components, indicating that there is no consensus on the correctness of the initial claim regarding the relationship between 'u sub z' and 'partial f/partial x times u sub x.'

Contextual Notes

There are unresolved questions about the assumptions underlying the representation of the tangent vector components and the specific definitions of the variables involved.

ericm1234
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on pages 14-15, in deriving the normal vector to a surface, they use a plane to cut the surface (the plane is parallel to the xz plane) then use the curve 'c' in the xz plane (this curve being where the plane intersects the surface), draw a tangent vector 'u' and want to use the components of 'u'. Now, they use an arbitrary length called 'u sub x' in the x direction (this again is in the xz plane) but WHY is the component in the z direction designated 'partial f/partial x times u sub x'? My question is NOT "why is the derivative of z with respect to x replaced with the partial derivative of f with respect to x", that I understand. But why in the first place is the change in the z direction a derivative times change in x?
 
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ericm1234 said:
on pages 14-15, in deriving the normal vector to a surface, they use a plane to cut the surface (the plane is parallel to the xz plane) then use the curve 'c' in the xz plane (this curve being where the plane intersects the surface), draw a tangent vector 'u' and want to use the components of 'u'. Now, they use an arbitrary length called 'u sub x' in the x direction (this again is in the xz plane) but WHY is the component in the z direction designated 'partial f/partial x times u sub x'? My question is NOT "why is the derivative of z with respect to x replaced with the partial derivative of f with respect to x", that I understand. But why in the first place is the change in the z direction a derivative times change in x?
"on pages 14-15" of what?

If ux is a vector in the (positive) x direction, then "the component in the z direction" cannot be "partial f/partial x time ux" because that is a vector in the x direction, not the z direction. Are you sure you are quoting correctly?
 
Pgaes 14-15 of 'div grad curl and all that', second edition however.
Let me rephrase:
there is a surface S in 3-d (x, y, z). This is cut by a plan parallel to the xz plane. This intersection of the plane and surface creates a curve C.
Now there is a picture showing the x and z axes with this curve C, and a tangent vector called U. U is decomposed into U sub X and U sub Z HOWEVER, U sub Z is 'equal' here to as 'partial f/ partial x' times U sub X.
So my question is why is U sub Z equal to partial f/partial x time U sub X.
 
Oh, and f refers to the 3-d surface: z=f(x,y). The second picture I referred to is a 2-d picture with the x and z axes, just to clarify.
 

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