(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A uniform cylinder, of radius 2a and moment of inertia $2Ma^2$ is free to rotate about its horizontal axis. A light, inextenzible string is wound round the cylinder and a particle of mass m is suspended on its free end. If the system is released from rest, find the acceleration of the particle.

2. Relevant equations

Torque(C)=Moment of inertia(I) x (angular accleration)$\alpha$.

3. The attempt at a solution

Resolving the tension in the string, we get T=mg-2ma(alpha)

Which gives upon calculating the angular acceleration (given that I=2Ma^2)

alpha=(mg)/(2am+Ma) which is somehow incorrect.

Can someone correct my error?

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# Homework Help: Question involving moment of inertia, rotation about a horizontal axis.

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