Question involving spring constant

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SUMMARY

The discussion centers on calculating the new length of a spring with a spring constant of 12000 N/m when a 65 kg weight is applied. The force exerted by the weight is calculated as 637.65 N using the equation f = m * g, where g is the acceleration due to gravity (9.81 m/s²). The displacement of the spring, calculated as x = 637.65 N / 12000 N/m, results in a change of approximately 0.053 m or 5.3 cm. This displacement is reasonable when considering the spring's original length of 30 cm.

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Phenom66
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Homework Statement


We have a spring that is 30cm with a spring constant of 12000N/m
and there is a 65 kg weight put onto this spring. What is the new length of the spring?


Homework Equations


f = k *changeof* x


The Attempt at a Solution


I tried to take 65kg times 9.81 to find Newtons (which is 637.65N)
so therefore 637.65 = 12000 *change of* x
and x = 637.65/12000
But something feels fishy about this, a spring doesn't move down just .053 m
 
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Phenom66 said:

Homework Statement


We have a spring that is 30cm with a spring constant of 12000N/m
and there is a 65 kg weight put onto this spring. What is the new length of the spring?


Homework Equations


f = k *changeof* x


The Attempt at a Solution


I tried to take 65kg times 9.81 to find Newtons (which is 637.65N)
so therefore 637.65 = 12000 *change of* x
and x = 637.65/12000
But something feels fishy about this, a spring doesn't move down just .053 m

Think about it for a moment longer. How big is 637.65 N compared to 12000 N?

Then convert .053 m into centimeters. Now does it seem so unreasonable?
 

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