Question involving spring constant

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Phenom66
Messages
1
Reaction score
0

Homework Statement


We have a spring that is 30cm with a spring constant of 12000N/m
and there is a 65 kg weight put onto this spring. What is the new length of the spring?


Homework Equations


f = k *changeof* x


The Attempt at a Solution


I tried to take 65kg times 9.81 to find Newtons (which is 637.65N)
so therefore 637.65 = 12000 *change of* x
and x = 637.65/12000
But something feels fishy about this, a spring doesn't move down just .053 m
 
Physics news on Phys.org
Phenom66 said:

Homework Statement


We have a spring that is 30cm with a spring constant of 12000N/m
and there is a 65 kg weight put onto this spring. What is the new length of the spring?


Homework Equations


f = k *changeof* x


The Attempt at a Solution


I tried to take 65kg times 9.81 to find Newtons (which is 637.65N)
so therefore 637.65 = 12000 *change of* x
and x = 637.65/12000
But something feels fishy about this, a spring doesn't move down just .053 m

Think about it for a moment longer. How big is 637.65 N compared to 12000 N?

Then convert .053 m into centimeters. Now does it seem so unreasonable?