Question involving the shell method

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SUMMARY

The discussion focuses on using the shell method to calculate the volume generated by rotating the region bounded by the curves y = x², y = 0, x = 1, and x = 2 about the line x = 1. The correct function for the height of the cylindrical shell is identified as x², leading to the integral V = 2π∫(x-1)(x²)dx from 1 to 2. The final computed volume is 17/2. This solution demonstrates the application of the shell method in calculus effectively.

PREREQUISITES
  • Understanding of the shell method in calculus
  • Familiarity with integral calculus
  • Knowledge of the functions y = x² and their graphical representation
  • Ability to perform definite integrals
NEXT STEPS
  • Study the shell method in detail, focusing on its applications in volume calculations
  • Practice integrating functions involving polynomial expressions
  • Explore the concept of rotating regions about different axes
  • Learn about other volume calculation methods, such as the disk and washer methods
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Students studying calculus, particularly those focusing on volume calculations using the shell method, as well as educators seeking to clarify these concepts for their students.

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Homework Statement


Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the given axis:

y = x2, y = 0, x = 1, x = 2, about x = 1

Homework Equations



V = 2[itex]\pi[/itex][itex]\int[/itex]xf(x)

The Attempt at a Solution



I am assuming based off the graph that my f(x) would be equal to 4-x2, but I am having difficulty figuring out the respective x value. Any help?
 
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Then I suggest you look at your graph again! Each shell, at a specific x, has a length ranging from y= 0 to [itex]y= x^2[/itex] so that its height is [itex]x^2- 0= x^2[/itex].
 
Wow... that was silly of me. That makes a lot more sense. So I would integrate 2[itex]\pi[/itex][itex]\int[/itex](x-1)(x2)dx from 1 to 2, which gives me an answer of 17/2. Thanks for the help.
 

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