Question: # of particles within an energy range below Fermi Energy.

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SUMMARY

The discussion focuses on calculating the number of conduction electrons in a 1 mm³ cube of gold with energies between 4.000 eV and 4.025 eV at 300K. The Fermi Energy for gold is established at 5.53 eV. The density of states, g(E), is derived using the formula g(E)dE = DE^(1/2)dE, where D is calculated as D = (8√2πMe^(3/2))/h³, resulting in g(E) = 6.79 x 10^37 Energy States/m³. The user seeks guidance on how to proceed with the integration to find the total number of electrons.

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Lil Dansn Man
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Homework Statement


Here's what the question says.

"Consider a cube of gold 1 mm on an edge. calculate the approximate number of conduction electrons in this cube whose energies lie in the range from 4.000 to 4.025 at 300k. Assume Ef(300K) = Ef(0)."



Homework Equations



Well, I know that n(E)dE = g(E)Ffd(E)dE, where g(E) is the density of states, and Ffd is the Fermi-Dirac probability.

Also, N/V = 0-inf∫ n(E)dE

and the Fermi Energy for gold is 5.53 ev


The Attempt at a Solution



Finding the Volume is easy, which is just V = (1e-3)^3

Then, I try to find g(E), which is g(E)dE = DE^(1/2)dE, where D =\frac{8*sqrt(2)*pi*Me^(3/2)}{h^3}

Using 4.00eV for E^(1/2) (and consequently converting it to Joules) I get g(E) = 6.79^37 Energy States/m^3.

Here's what I did in wolfram alpha language:

here's D: http://www.wolframalpha.com/input/?i=(8*sqrt(2)*pi*(9.109e-31)^(3/2))/(6.626e-34)^3)

Now here's D*E^(1/2): http://www.wolframalpha.com/input/?i=1.06e56*(4*1.602e-19)




Pretty much my question is "What do I do next?" Due to N/V equaling an integral, I'm a little iffy on what to do.

Thanks :)
 
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Hmm sorry, I actually only multiplied by E, not E^1/2...


Here's E^1/2: 1.06e56*((4*1.602e-19)^(1/2))
 

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