Question on a form of the Euler constant

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SUMMARY

The discussion centers on proving the equation \(\int_{1}^{\infty}\frac{u-[u]}{u^2}du=1-\gamma\), where \(\gamma\) represents the Euler Constant and \([u]\) denotes the floor function. A proposed method involves transforming the left-hand side into a summation: \(\sum_{i=1}^{\infty} \int_{i}^{i+1}\frac{u-i}{u^2}du\). This approach aims to simplify the integral for easier evaluation and verification of the relationship with the Euler Constant.

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I was wondering how I would go about proving this equation:
[tex]\int_{1}^{\infty}\frac{u-<u>}{u^2}du=1-\gamma</u>[/tex] where [tex]\gamma[/tex] is the Euler Constant, and [tex][/tex] is the floor function
 
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Maybe, turning the left-hand side into
[tex]\sum_ {i=1} ^ \infty {\int_{i}^{i+1}\frac{u-i}{u^2}du }[/tex]
 

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