Question on electric filed of an insulating cylinder

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SUMMARY

The discussion focuses on calculating the electric field of an infinitely long insulating solid cylinder with a non-uniform spherically symmetric charge distribution defined by ρ(r) = (ρ(0)/R)r. The participants clarify that for distances greater than the cylinder's radius (r > R), the electric field can be determined using Gauss' law, while for distances within the cylinder (r < R), the enclosed charge must be calculated to apply Gauss' law correctly. The misunderstanding regarding the charge density function is addressed, emphasizing the need to accurately interpret the linear relationship of charge density with respect to radius.

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loba333
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An infinitely long insulating solid cylinder of radius R contains a non-uniform
spherically symmetric charge distribution, whose density is given by
rho r = rho(0) r/ R. Calculate the electric field a distance r from its axis:
(i) when r > R;
(ii) when r < R.

Can some please expalin to me how to do this. i could be able to do it for a sphere with a charge q but the formula (rho r = r(0) r/ R) has thrown me off.

Heres the question
http://i1200.photobucket.com/albums/bb327/loba333/photobucket2.png

Cheers guys !
 
Last edited:
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Why is there an r either side of the quation ?
 
loba333 probably meant rho(r) = (rho(0)/R)r, as in rho a linear function of r.
 
no one ?
 
The problem states that the cylinder is insulating, with a given charge distribution throughout. So for iii) your assumption about the enclosed charge being zero for r < R is invalid.

You're going to want to find expressions for the total charge contained within the Gaussian surface per length L, then apply Gauss' law to find the form of the electric field.
 

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