1. The problem statement, all variables and given/known data Question: If an 80kg object experiences a normal force of 510N, and an unknown angled pull force. The coefficient of friction is 0.33. If the object moves with a constant velocity, what is the direction (angle) and magnitude (size) of the pull force? m=80kg a=0m/s Fx=FcosΘ Fy=FsinΘ μ(mu)=0.33 Fk=510N x 0.33 g=-9.81 weight=80kg x 9.81 2. Relevant equations Fx-fk=max (the "x" is a coefficient) Fy-fk=may (the "y" is a coefficient) Fs=μs x Fn Fk=μk x Fn 3. The attempt at a solution First I set up a simultaneous equation using Fx-fk=max and Fy-fk=may. This is what I got. 80kg+0m/s=FcosΘ -(510N)(0.33) 80kg+0m/s=FsinΘ -(80kg)(9.81) This is where I get stuck. I am really bad at solving simultaneous equations.