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Question on Work done by horse pulling a wagon.

  1. Oct 28, 2013 #1
    1. The problem statement, all variables and given/known data
    How much work did a horse do that pulled a 200-kg wagon 50 km without acceleration along a level road if the effective coefficient of friction was 0.060?


    2. Relevant equations
    W=Fnet * d

    Force of friction= µmg

    3. The attempt at a solution

    W=200*9.8-(200*9.8*0.060)*50,000
    =92120000


    Correct answer is supposed to be 5.9*106
     
  2. jcsd
  3. Oct 28, 2013 #2
    Your equation doesn't make sense. Where did that first term come from? The correct answer should just be the second term with a plus sign. If you recalculate the expression you gave, you will find that you evaluated it incorrectly.

    Chet
     
  4. Oct 28, 2013 #3

    tiny-tim

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    Homework Helper

    Hi Daaniyaal! :smile:
    work done is force "dot" displacement

    what is the dot product of the vertical weight with the horizontal displacement? :wink:
     
  5. Oct 28, 2013 #4
    I guess I unnecessarily put in the force needed to move the wagon without friction opposing the movement. Oopsies

    :blushing:

    I feel embarrassed >.>

    Also, thank you :)
     
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