A child pulls a wagon by the handle along a flat sidewalk.

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SUMMARY

The discussion focuses on calculating the mechanical work done by a child pulling a trolley with a force of 80.0 N at an angle of 30.0° over a distance of 12 m. The calculated work done by the child is 148 J, derived from the equation W = F * cos(θ) * d. Additionally, the total work done on the trolley must account for the force of friction, which is 34 N, indicating that the net work done is the sum of the positive work by the child and the negative work due to friction.

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SilentWind12
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Homework Statement


A child pulls a trolley by the handle along a flat sidewalk. She exerts a force of 80.0 N at an angle of 30.0° above the horizontal while she moves the wagon 12 m forward. The force of friction on the trolley is 34 N.

Homework Equations


(a) Calculate the mechanical work done by the child on the trolley.
(b) Calculate the total work done on the trolley

The Attempt at a Solution


W=F(cos)
80 cos(30)[/B]
W=Fcosdeltad
W=80 N(cos30)(12)
=148J

b)Idk how to do it.
 
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SilentWind12 said:
W=80 N(cos30)(12)
=148J
Try that last step again, taking note that it is 30 DEGREES.
For b), what else is doing work on the trolley? How much work? Positive or negative?
 
SilentWind12 said:
(b) Calculate the total work done on the trolley
This could be worded: Calculate the net work done on the trolley.
 

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