Question regarding artificial satellites

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Artificial satellites can enter lower orbits by reducing their velocity, which aligns with the principle that orbital period depends on radius. While decreasing radius increases gravitational force, leading to higher acceleration, the relationship between velocity and radius is complex. In circular orbits, speed is highest at lower altitudes and decreases as altitude increases. If a satellite reduces speed while in a circular orbit, it transitions to an elliptical orbit, moving closer to Earth at one point. To return to a circular orbit at a lower altitude, additional propulsion is required.
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Hey guys,

I just had a question regarding artificial satellites:

From what I understand, satellites are able to enter into a lower orbit by reducing their velocity, which makes sense because of V=2*pi*r/T

However, decreasing radius should also increase Fg and thus acceleration and thus velocity because of Fg=GMm/r^2 and also directly if you make Fc=Fg, then v^2=GM/r

I am quite confused with this because It seems that the velocity and radius of a satellite are both inversely and also directly proportionate at the same time. Could someone please explain to me how this works?

Thanks a tonne :)
 
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The period is not a constant, it depends on radius. So you first equation does not mean what you think.
Actually, for circular orbits, the speed is highest in low orbit and decreases for higher orbits. As shown in your last equation.

But circular orbits are not the only possible ones. If the satellite is in circular orbit and you decrease the speed the orbit will became elliptic. The ellipse will be tangent with the original orbit in the point where you change speed so on this elliptical orbit the satellite will move closer to Earth.
To go back to a circular orbit but closer to Earth you will need to fire the engines one more time.
 
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