Questioning My Conception of Surface Tension

Click For Summary
SUMMARY

This discussion centers on the mechanics of surface tension as it relates to a needle floating on water. The key formula derived is T = F/2L, where T represents surface tension, F is the force needed to uphold the needle, and L is the needle's length. Participants clarify that surface tension acts upward against gravity, necessitating an external force to pull the needle from the water. The conversation emphasizes the energy cost associated with increasing the water-air interface area when the needle is removed.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Familiarity with surface tension concepts
  • Basic knowledge of forces and energy in physics
  • Ability to interpret diagrams related to fluid behavior
NEXT STEPS
  • Study the relationship between surface tension and force in fluid mechanics
  • Explore the concept of energy associated with surface area changes in liquids
  • Learn about the effects of gravity on floating objects in fluids
  • Investigate the mathematical derivation of forces acting on objects at fluid interfaces
USEFUL FOR

Students and professionals in physics, particularly those focusing on fluid mechanics, as well as educators seeking to clarify concepts of surface tension and force interactions in liquids.

Ezio3.1415
Messages
159
Reaction score
1
I was solving a problem from fluid mechanics... But that led me to question my conception abt surface tension...
The problem stated that the max force needed to uphold a needle(ignore its weight)from the water surface is F... The needle is L m long... What is the surface tension?
They found it by T=F/2L
I know how surface tension works... But I fail to grasp this problem... Why do we need force at all to take out the needle?
 
Physics news on Phys.org
I just did an experiment... The needle press down a little on the water... Water gets a little dowm near the edge...so surface tension has a perpendicular downward component... So I need to give an F to pull up the needle... Am I right?
 
The source of surface tension is the fact that water (or other liquid) molecules like to be near to each other. A water molecule at the water-air interface has a higher energy than a molecule that is surrounded by other water molecules. Thus, to increase the area of the water-air interface costs energy. When you pull the needle away from the water, you are doing exactly that - you distort the water surface such that the water-air interface becomes larger. This costs energy, so you need to apply a force.
 
I just did an experiment... The needle press down a little on the water... Water gets a little dowm near the edge...so surface tension has a perpendicular downward component... So I need to give an F to pull up the needle... Am I right?

In this experiment, it is gravity that pulls the needle down. Surface tension is acting vertically upwards, preventing it from sinking.

Edit - I think some diagrams to show the shape of the water surface around the needle might be informative. I'll draw some and add them shortly.
 
http://oi50.tinypic.com/s1p7iv.jpg

In this diagram, I have attempted to show the needle on the water surface, subject to gravity and surface tension. I have shown it from three directions, the two horizontal views are rotated 90 degrees from each other.

Moving the needle down by a small distance distorts the water surface which creates a larger water-air interface. This interface has energy associated with it, E = Aγ, where A is the area of new surface and γ is the surface tension of the water. If you differentiate that equation with respect to the vertical direction, you will obtain the expression for the upward force on the needle due to surface tension.

In your original problem, you were considering pulling the needle up out of the water. In that case, the water would simply bulge up instead of down and the force will hold the needle down instead of pulling it up.
 
I am again back to my previous confusion... If surface tension acts upward,then why do I have to pull with a force when the needle is weightless...
"In your original problem, you
were considering pulling the
needle up out of the water. In
that case, the water would
simply bulge up instead of
down and the force will hold
the needle down instead of
pulling it up."
I didn't understand this part...
 
http://oi50.tinypic.com/dyohup.jpg

In this diagram, I have tried to illustrate the difference between what happens when gravity is pulling the needle down and what happens when you pull it up with some external force. Fst is surface tension and Fext is whatever external force you use to pull at it.

It might be useful to think of the water surface as a sheet of elastic material. When gravity pulls the needle down, it pulls the sheet down a bit with it. The sheet wants to spring back up, so it exerts a force in that direction.

When you pull the needle up with some external force (with a string attached to it or whatever), you pull the surface up with it. The sheet wants to spring back down, so it exerts a force downwards. If the force you exert is strong enough, the restorative force of the sheet can't hold the needle, the sheet breaks and you lift the needle away.
 
Thank you very much for the help... The figure explains it all...
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
39
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K