Hi everyone, While studying surface tension I came across a(numerical example) problem which asks to find the force required to pull a circular glass plate of some given radius from the surface of water(assume plane of plate on water surface). Value of surface tension of water is also given in problem. The solution was done by simply multiplying surface tension of water with length of circumference. And it ends. Now what I am thinking is that what would be the solution if instead of water the circular plate were in mercury which do not stick on glass. Since mercury does not stick(wet) on glass (as cohesive force of mercury molecules is much greater than adhesive force between mercury and glass) therefore no or very little force should be required to remove plate from mercury than that required for glass. The force required to remove glass plate from water would be high because molecules of water strongly holding the glass and will not leave it so force is required to break cohesive force of water that is surface tension of water. But in case of mercury, mercury molecules do not hold glass so tightly therefore while trying to remove plate from mercury, the mercury molecules leave the plate even when the applied force is less than that required to break the cohesive force between mercury molecules. This is what I suppose. Is my understanding true? Regards! Thanks a bunch.