Questions About Choosing a Shunt Resistor

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SUMMARY

This discussion focuses on the proper selection and implementation of a shunt resistor for power analysis in circuits operating at 3.3 volts. The user initially employed a 10 Ohm shunt resistor with a 5V power source, leading to confusion regarding voltage regulation and measurement techniques. Key insights include the necessity of retaining bypass capacitors and the importance of selecting a shunt resistor that minimally impacts the circuit's voltage supply. The conversation highlights the need for clearer communication of the user's objectives to provide effective guidance.

PREREQUISITES
  • Understanding of shunt resistor applications in power measurement
  • Knowledge of voltage regulation, specifically 3.3V and 5V systems
  • Familiarity with oscilloscope usage for current and voltage measurements
  • Basic circuit design principles, including the role of bypass capacitors
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  • Research optimal shunt resistor values for minimal circuit disturbance
  • Learn about voltage regulator functionality and selection criteria
  • Explore advanced oscilloscope techniques for power measurement
  • Study circuit design best practices for power analysis setups
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Electronics engineers, circuit designers, and hobbyists involved in power analysis and measurement in electronic circuits.

Yoyo G
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I'm trying to do a power analysis on my target, which runs on 3.3 volts. Without the resistor, the average current while running is roughly 140mA.
I used a 10Ohm resistor as a shunt resistor with a 5V power source. The voltage difference between VCC PIN and GND was measured using a shunt resistor linked between 5V and the target VCC pin. (The decoupling capacitors have been removed.) On the other hand, the oscilloscope lacked a proper power consumption line.
Is there a problem with my setup? Is there any guidance on how to choose a shunt resistor?
 
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Uh what? You are using a shunt resistor to try to lower your 5V source to 3.3V? Are you serious?
 
What is the target ?
Where is the usual 3.3 V regulator ?
Can you measure the input current to the 3.3 V regulator ?
Keep the bypass capacitors, do not disconnect them.
 
What? This doesn't make much sense to me. What are you trying to do? Can you post a schematic or block diagram?
Yoyo G said:
the oscilloscope lacked a proper power consumption line.
What is that? I've used a lot of oscilloscopes and measure current many times, but I don't know what you are referring to here. Are you wanting to use the scope to multiply current and voltage to display power? Why would you need that for a fixed PS voltage?

I think you're not communicating your question well enough for us to help. Tell us more.
 
Feels like quite a mess. Based on the description, you wish to see some current-over-time diagram, or possibly power-over-time diagram? At what time scale?

The most fundamental problem with your setup is, that while serial resistors would split power and (for resistors! In theory!) it would enable measuring the power on the other resistor, when it's 3.3V and VCC (means an integrated circuit) it is no longer working since an IC requires constant voltage supply to function properly.

So you need to pick a shunt which is small enough to not disturb the VCC during measurement. 10Ohm would sure not do. You need further tricks to make this work, but we need to know more to know what tricks will you need.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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