Questions in Newtons Laws and Thermodynamimcs.

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A 15 kg wagon being pulled with a force of 45 Newtons accelerates at 2 m/s², resulting in a net force of 30 Newtons, calculated using F_net = ma. For the temperature of mixed water, the specific heat of water is necessary to apply the mc(delta)t equation, which is not provided in the question. According to Newton's first law, if the net force is zero, the object will maintain its current velocity, not necessarily come to rest. At twice the Earth's radius, the mass remains the same, but the weight decreases due to reduced gravitational force, which can be calculated using the gravitational formula. Understanding these concepts is crucial for test preparation in physics.
nasar176
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Hi there can anyone please explain to me these questions I am really confused about them.

Q: A 15 kg wagon is pulled to the right a force of 45 Newtons. the wagon accelarates at 2 m/s2. what is the net (unbalanced) force accelerating the wagon? (f of g is 10)

the book says the answer is 30, but i have no idea why?

Q: If 200 grams of water at 48 C is mixed with 100 grams of water at 30 c, the resulting temp. of the water is?

I wanted to use the mc(delta)t equation but they don't give the specific heat of water in the question.

Q: If all of the forces acting on an object balance so that the net force is zero, then:
A) the object must be at rest (i chose this answer but its wrong IDK why)
B)the object speed will decrease
c)
D)
E) none of the above( this is the answer according to the book.

Q: at the surface of the earth, an object of mass m has weight w. If this object is transported to an altitude that's twice the radius of the Earth then at the new location the mass and weight is?

i said the mass is m because its an intrinsic property but i don't know what the wieght would be.

please help me out, i am studying for a test and i really need to clear these concepts.
thanks
 
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Maybe. m=15 kg and the force F=45N, it accelerates by 2m/s/s then
F_{net} = ma = 15\text{kg}\times 2\text{m/s^2} = 30 \text{N}
 
The 2nd question. Find it yourself, it must be this equation you are to use, else it is complicated I think.
3rd question: Newtons 1st law says that a particle which is affected by no force is continuing with the same velocity along a straight line, thus if it had e.g. v = 400m/s as velocity it would still be moving with that velocity not increasing nor decreasing.
4. I think you should use the gravitational formula F_{grav} = -G\dfrac{mM_{earth}}{r} then compare that force to the usual F = mg
 
ok thanks
 
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