Quick error propagation problem

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SUMMARY

The discussion focuses on the propagation of error in calculating the x-component of a velocity vector, specifically using the formula V*cos(θ). The values provided are a velocity (V) of 0.048 m/s and an angle (θ) of 27 degrees, with uncertainties of ±0.0003 for velocity and ±0.5 degrees for the angle. The key conclusion is that the angle's uncertainty must be converted from degrees to radians to accurately apply the derivative relation, as the derivative of cosine with respect to theta is valid only in radians.

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mjolnir80
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Homework Statement


we are trying to find the x -component of a velocity vector (V*cos[tex]\theta[/tex])
our uncertainty for the velocity is +-.0003 and for the and it is .5(in degrees)
how do we propagate the error for this
v=.048 while [tex]\theta[/tex] =27 degrees



Homework Equations





The Attempt at a Solution


using partial derivatives :
(vSin[tex]\theta[/tex]).5 (degrees)+ (cos[tex]\theta[/tex]).0003=
(0.048*sin27)0.5+(cos27).0003=0.02
the problem is this is a really big uncertainti compared to the answer and i was just wondering whether i did this right?
 
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The method looks fine except that you need to convert your error to radians, as the relation [tex]\frac{d}{d \theta} \cos \theta=- \sin \theta[/tex] is only true when [itex]\theta[/itex] is in radians.
 
thanks allot!:smile:
 

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