Propagation of Error and Relative Error

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Homework Help Overview

The discussion revolves around a physics problem involving the propagation of error and relative error in projectile motion. The original poster attempts to calculate the accuracy of the range estimation for a projectile launched at a specific angle and initial velocity, while considering the relative accuracy of the angle measurement.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the derivative of the range equation and its implications for calculating relative error. There are questions about the use of cotangent in the context of the problem, and some participants express confusion regarding the units of measurement for angles, particularly the distinction between degrees and radians.

Discussion Status

Participants are actively engaging with the problem, raising questions about the correct approach to calculating the angle and its impact on the final answer. There is a recognition of the importance of using radians in calculations involving trigonometric functions, and some guidance has been provided regarding unit conversions.

Contextual Notes

There is an ongoing exploration of the implications of using different units for angles, with specific reference to the potential for obtaining results that exceed 100% accuracy. The original poster is grappling with the implications of their calculations and the necessary conversions for accurate results.

GoCubs12
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Homework Statement



2) A student is performing an angry bird experiment in real life. He calculates the range of the projectile by shooting the bird with a 30 degree angle and an initial velocity of v0 = 20 m/s.

a) If the relative accuracy of setting the projectile angle is delta theta/theta = 0.05, what would be the accuracy of the range estimation?

Homework Equations



delta R= derivative of range equation*delta theta

R=v^2/g*sin(2*theta)

The Attempt at a Solution



I determined the derivative of the range equation and got v^2/g*2*cos(2*theta). I then divided this by the original function and got delta x/x=2cot(2*theta)*delta theta. This is the point I am stuck at. Normally with the problems I have done so far I would get to this point and be able to substitute in the given value of delta theta/theta. However, the cot is throwing me for a loop and I just can't to find a way through it and past that point. All advice is appreciated. Thanks!
 
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What is your problem with cotangent? You lost sight of what you are suppose to be looking for but you are on the right track.
 
gleem said:
What is your problem with cotangent? You lost sight of what you are suppose to be looking for but you are on the right track.

My problem is that if I put theta into the cot and solve the relative accuracy of the angle for delta theta and put that into the equation as well, I get a number over 100% which doesn't seem like it is even remotely correct and I just can't think of any other way to go about it.
 
What value are you using for dθ?
 
gleem said:
What value are you using for dθ?

The only value I could think of was to solve dTheta/Theta for dTheta. So the value is really 30*0.05.
 
That is you problem. Can you figure out why? Think units.
 
gleem said:
That is you problem. Can you figure out why? Think units.

I know that the answer I am getting currently would be in degrees which is incorrect but I can't seem to find a way to solve for dTheta without it encountering that issue. Is there another way to figure out dTheta?
 
dθ = .05⋅θ What units should you be using for θ? What other unit for angles is there?
 
gleem said:
dθ = .05⋅θ What units should you be using for θ? What other unit for angles is there?

Using radians I get a final answer of 0.0302. How do you know you need to use radians instead of degrees though. I know that the answer seems more reasonable now but in the future how can I tell?
 
  • #10
GoCubs12 said:
Using radians I get a final answer of 0.0302. How do you know you need to use radians instead of degrees though. I know that the answer seems more reasonable now but in the future how can I tell?
If you take the derivative of a trig function the assumption is that the angle is expressed in radians. In those units, the first derivative of sine is cosine.

If you have a trig function and the angle is in degrees, you will need to insert a unit conversion factor of pi radians per 180 degrees each time you integrate or take a derivative.

It's usually easier to always do the math using radians and to convert the inputs and outputs as required.
 
  • #11
GoCubs12 said:
Using radians I get a final answer of 0.0302. How do you know you need to use radians instead of degrees though. I know that the answer seems more reasonable now but in the future how can I tell?

Always use radians. 1 deg = π/180 rad. When looking up values for trig functions where degrees is the specified unit of the table or calculator setting change radians to degrees using 1 rad. = 180/π deg. (verify your calculator setting)
 

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