Quick question about centers of instantaneous velocities

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SUMMARY

The discussion focuses on the instantaneous center of velocities in a mechanical system involving bodies B1, B2, and B3. When body B is moving horizontally at speed Vb, the instantaneous center of B2 is analyzed in relation to the angular velocity of B3, which is pinned at point C. The conclusion drawn is that the angular velocity of B3 approaches zero as body B2 becomes vertical, indicating a transition in motion direction as the angle theta decreases.

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Homework Statement


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If at some time t, the position of B (the intersection between bodies B1 and B2) is located directly below the connection between bodies B2 and B3. B is moving to the right at a speed of Vb. What happens to the instantaneous center of B2, and what can this tell you about the angular velocity of B3? (Note: body B3 is pinned at the location C and B is restricted to move in the horizontal direction). Explain.

Homework Equations


Velocity of the instant center is 0.
v = rw, where v = velocity, r = distance to the point, and w = angular velocity

The Attempt at a Solution


Since the perpendicular path of the velocity of B passes through point A, and the velocity of A is restricted to be moving tangent to the circular path around C, the only thing that makes sense to me is if B3 has an angular velocity to be 0 and the velocity at A is zero. The reason why is because at any moment prior to the instant that B2 is vertical, the angular velocity of B3 has to be in one direction since theta is growing, but as the body becomes more and more vertical, the magnitude of this velocity decreases until it has to reach a zero point since any point following this instant will have the angular velocity begin to change in the opposite direction (theta will be getting smaller).

I am a little concerned that my reasoning here may be off though, or that I'm missing something important.
 
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I agree with your analysis.
 
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mfb said:
I agree with your analysis.

Thanks for looking it over.
 

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