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Quick question about simplifying a circuit

  • Thread starter Zondrina
  • Start date
  • #1
Zondrina
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Homework Statement



I want to see if I'm reducing the following circuit correctly.

Homework Equations





The Attempt at a Solution



The two outer resistors are in series:

##R_{56} = R_5 + R_6##

Now the outer resistors would be directly wired on each end after simplifying. Hence:

##R_{456} = (\frac{1}{R_4} + \frac{1}{R_{56}})^{-1}##

Series again:

##R_{2456} = R_2 + R_{456}##

Parallel:

##R_{32456} = (\frac{1}{R_3} + \frac{1}{R_{2456}})^{-1}##

Series:

##R_{132456} = R_1 + R_{32456}##

Now if we had the emf we could find the current and work backwards if needed.
 

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Answers and Replies

  • #2
Orodruin
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Looks reasonable. Looking for the current i6 there may be easier ways though. They should all amount to the same in the end.
 

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