- #1

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**1. my function is: f(x)=log 1.5 (-.76x+305). f(x)= log base 1.5 of -.76x+305**

**3. How do i differentiate it? here is what i have so far: (1/((-.76x+305)ln1.5))*(-.76/dx)**

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- Thread starter KV-1
- Start date

- #1

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- #2

Dick

Science Advisor

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- #3

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so it seems i just multiply the derivative of [log base 10 (-0.76x+305)] by that number!

- #4

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((-0.76)(log(e)))/((-0.76x+305)(log(1.5))

thats the answer i think.... in case anyone is curious

thats the answer i think.... in case anyone is curious

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