If I throw a ball vertically in the air and catch it again at the exact same height after 3.6 seconds. (looking away from air resistance) So the question is: 1. How big is the starting speed? (v0) And how far in the air would the ball go? 2. If we were not to catch the ball it would've hit the floor after 3.9 seconds after we threw it. How far away from the floor is that starting point? I think if you put v = 0 (when it's at its highest point) and you got g ofc (9.81m/s) But I really can't figure it out.. which formulas to use etc, I feel like I have too little information? But if I set v = 0 and calculate the time and the distance to the highest point I think I can solve it... only problem is that I don't know how to calculate the first part of the problem.