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Quick Question on Variation of Parameters Differential Equations

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1. Homework Statement

What do you do if one of the roots to the characteristic equation of a differential equation is zero when using variation of parameters?

2. Homework Equations



3. The Attempt at a Solution

The problem I encountered this in is

y" - y' = 4t

Characteristic equation

r2 - r = 0

so

r = -1 , 0

Therefore

y1 = e-t

but

y2 = 0

which would make the Wronskian zero.

Any thoughts?
 

Answers and Replies

rock.freak667
Homework Helper
6,230
31
Your other solution would be y2=e^(0*t) = 1
 

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