Can the covariant components of a vector, v, be thought of as v multiplied by a matrix of linearly independent vectors that span the vector space, and the contravariant components of the same vector, v, the vector v multiplied by the *inverse* of that same matrix?(adsbygoogle = window.adsbygoogle || []).push({});

thinking about it like that makes it easy to see why the covariant and contravariant components are equal when the basis is the normalized mutually orthogonal one, for example, because then the matrix is just the identity one, which is its own inverse.

that's what the definitions i read seem to imply.

Thanks!

**Physics Forums - The Fusion of Science and Community**

# Quick, simple question about contraviant and covariant components

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Quick, simple question about contraviant and covariant components

Loading...

**Physics Forums - The Fusion of Science and Community**