Quick Trig Question: Solving for θ=-Pi/4

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The discussion centers on understanding how θ = Tan^-1(-2/2) results in θ = -π/4. The inverse tangent function is defined for angles between -π/2 and π/2, and the tangent of -1 corresponds to -π/4 on the unit circle. Participants emphasize the importance of a solid grasp of basic trigonometry to tackle calculus problems effectively, particularly when dealing with integrals and trigonometric substitutions. They recommend reviewing precalculus materials or utilizing online resources like Khan Academy for better comprehension. A strong foundation in trigonometry is crucial for success in calculus.
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Homework Statement


I am working through a calc 2 problem. I managed to get here without really completely understanding trig. There was a point in the problem where θ=Tan-1(-2/2) = -Pi/4. How does this work?

Homework Equations


I do not know any relevant equations


The Attempt at a Solution


I really have no clue. I have done research countless times.
 
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For purposes of the Inverse Tangent, the Tangent function is restricted to the angle values from negative pi/2 to positive pi/2. A tangent of (-2/2) is the same as the tangent of (-1), and just relating this to the unit circle, this ange is -π/4.
 
mrshappy0 said:

Homework Statement


I am working through a calc 2 problem. I managed to get here without really completely understanding trig. There was a point in the problem where θ=Tan-1(-2/2) = -Pi/4. How does this work?
I would advise you to spend some time reviewing basic trigonometry, especially in relation to the trig functions and their inverses. If you are trying to work through integrals without a solid understanding of trig, you will really have a hard time, particularly when it comes to trig substitutions.

Some time invested in reviewing your old precalc book would really pay off. Alternatively, there are many helpful videos about a variety of topics in math at khanacademy.org. A good place to start would be http://www.khanacademy.org/#trigonometry.
 

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