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## Homework Statement

[tex]y=\frac{8x^4-5x^2-2}{4x^3}[/tex]

Find y'.

**2. The attempt at a solution**

[tex]y=\frac{8x^4-5x^2-2}{4x^3}[/tex]

[tex]y'=\frac{(32x^3-10x)(4x^3)-(12x^2)(8x^4-5x^2-2)}{(4x^3)^2}[/tex]

[tex]y'=\frac{128x^6-40x^4-96x^6+60x^4+24x^2}{16x^6}[/tex]

[tex]y'=\frac{32x^6+20x^4+24x^2}{16x^6}[/tex]

[tex]y'=\frac{4x^2(8x^4+5x^2+6)}{4x^2(4x^4)}[/tex]

The 4x

^{2}gets cancelled out.

Finally,

[tex]y'=\frac{8x^4+5x^2+6}{4x^4}[/tex]

Did I do it right?

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