Undergrad Quotient law and the curl in index notation

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The curl in index notation can be expressed as (\nabla \times \vec v)^i = \epsilon^{i j k} \partial_j v_k, where the last equality holds due to the properties of the Levi-Civita symbol. The discussion raises a question about the application of the quotient law, suggesting that it implies \partial_j v_k is a tensor, which seems incorrect. It is clarified that the quotient law does not apply in this context because the Levi-Civita symbol, \epsilon, is not an arbitrary tensor. The subtlety lies in the specific properties of \epsilon that differentiate it from standard tensor operations. Understanding these nuances is crucial for correctly applying index notation in vector calculus.
SiennaTheGr8
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In index notation, the curl can be expressed in a way where the quotient law would seem to "fail." There must be a subtlety that I'm missing.
If I'm not mistaken, the curl can be expressed like this in index notation:

##(\nabla \times \vec v)^i = \epsilon^{i j k} \nabla_j v_k = \epsilon^{i j k} (\partial_j v_k - \Gamma^m_{j k} v_m) = \epsilon^{i j k} \partial_j v_k ##

(where the last equality is because ##\epsilon^{i j k}\Gamma^m_{j k}## is both symmetric and anti-symmetric in ##j## and ##k##). But now with ##(\nabla \times \vec v)^i = \epsilon^{i j k} \partial_j v_k##, doesn't the quotient law say that ##\partial_j v_k## is a tensor, even though it obviously isn't? Clearly I'm wrong. Is there a subtlety to the quotient law that I'm missing?
 
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Quotient law is not applicable here because ##\epsilon## is not an arbitrary tensor.
 
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