Quotient rule with additional condition

  • Thread starter Thread starter Fluidman117
  • Start date Start date
  • Tags Tags
    Condition quotient
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
7 replies · 2K views
Fluidman117
Messages
34
Reaction score
0

Homework Statement



I am working on chemical reaction engineering problem and it involves some math, which I am not able to figure out...

I have to find the residence time for maximum production, which is in the case when : (dη_p)/dτ=0

I have to find the τ (residence time).

Homework Equations



η_p=0.1τ/(1+0.4τ+0.04τ^2)

The Attempt at a Solution



I figure I have to use the quotient rule:

d[f/g]=(f'g-fg')/g^2

f=0.1τ
g=1+0.4τ+0.04τ^2

When I use the rule, I come up with an number which is not the same as in the answers. The reason is I think that I don't know how to take into account the condition that (dη_p)/dτ=0
 
Physics news on Phys.org
When you say the derivative equals zero, do you mean this:

0=(f'g-fg')/g^2

0=[0.1(1+0.4τ+0.04τ^2)-(0.1τ)(0.4+0.08τ)]/g^2
0=0.1-0.004τ^2/g^2

0.1-0.004τ^2=0

and solving for τ=5 , which is the correct answer.

However, I don't understand why g^2=0 ?
 
I don't have any scientific reasoning behind my logic, but basically that is the only way I could see that I come up with the answer given in the book.If I subsitute g^2=(1+0.4τ+0.04τ^2)^2 and using the formula
(a+b+c)^2= a^2+b^2+c^2+ 2(ab+bc+ca)

I end up with

0=(f'g-fg')/g^2=(0.1-0.004τ^2)/(1+0.8τ+0.24τ^2+0.032τ^3+0.0016τ^4)

What would be the next step from here?
 
Fluidman117 said:
When you say the derivative equals zero, do you mean this:

0=(f'g-fg')/g^2

0=[0.1(1+0.4τ+0.04τ^2)-(0.1τ)(0.4+0.08τ)]/g^2
0=0.1-0.004τ^2/g^2

0.1-0.004τ^2=0

and solving for τ=5 , which is the correct answer.

However, I don't understand why g^2=0 ?

If g^2 = 0, the derivative is undefined. The quantity (f'g - fg') must be 0 to satisfy the equation.
 
SteamKing said:
If g^2 = 0, the derivative is undefined. The quantity (f'g - fg') must be 0 to satisfy the equation.
To elaborate on what SteamKing said, the basic idea is that if a/b = 0, then a = 0. Of course, b cannot be 0.
 
Thanks everyone!