Quotient rule with additional condition

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Homework Help Overview

The original poster is working on a chemical reaction engineering problem that involves finding the residence time for maximum production, specifically when the derivative of a function related to production is equal to zero. The function provided is a quotient of two expressions involving τ.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the quotient rule for derivatives and the implications of setting the derivative to zero. There are attempts to clarify the conditions under which the derivative is defined and the significance of the denominator in the derivative expression.

Discussion Status

There is ongoing exploration of the mathematical reasoning behind the derivative and its implications. Some participants have provided insights into the algebraic manipulation required to analyze the problem further, while others have raised questions about assumptions regarding the denominator.

Contextual Notes

Participants are navigating the complexities of the quotient rule and its application in this specific context, with some uncertainty about the conditions under which the derivative is defined. There is mention of a specific answer from a textbook that some are trying to reconcile with their calculations.

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Homework Statement



I am working on chemical reaction engineering problem and it involves some math, which I am not able to figure out...

I have to find the residence time for maximum production, which is in the case when : (dη_p)/dτ=0

I have to find the τ (residence time).

Homework Equations



η_p=0.1τ/(1+0.4τ+0.04τ^2)

The Attempt at a Solution



I figure I have to use the quotient rule:

d[f/g]=(f'g-fg')/g^2

f=0.1τ
g=1+0.4τ+0.04τ^2

When I use the rule, I come up with an number which is not the same as in the answers. The reason is I think that I don't know how to take into account the condition that (dη_p)/dτ=0
 
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The derivative has to be zero, that means an equation for τ, easy to solve. Show your further work please.

ehild
 
When you say the derivative equals zero, do you mean this:

0=(f'g-fg')/g^2

0=[0.1(1+0.4τ+0.04τ^2)-(0.1τ)(0.4+0.08τ)]/g^2
0=0.1-0.004τ^2/g^2

0.1-0.004τ^2=0

and solving for τ=5 , which is the correct answer.

However, I don't understand why g^2=0 ?
 
g^2 is NOT 0. What makes you think it is?
 
I don't have any scientific reasoning behind my logic, but basically that is the only way I could see that I come up with the answer given in the book.If I subsitute g^2=(1+0.4τ+0.04τ^2)^2 and using the formula
(a+b+c)^2= a^2+b^2+c^2+ 2(ab+bc+ca)

I end up with

0=(f'g-fg')/g^2=(0.1-0.004τ^2)/(1+0.8τ+0.24τ^2+0.032τ^3+0.0016τ^4)

What would be the next step from here?
 
Fluidman117 said:
When you say the derivative equals zero, do you mean this:

0=(f'g-fg')/g^2

0=[0.1(1+0.4τ+0.04τ^2)-(0.1τ)(0.4+0.08τ)]/g^2
0=0.1-0.004τ^2/g^2

0.1-0.004τ^2=0

and solving for τ=5 , which is the correct answer.

However, I don't understand why g^2=0 ?

If g^2 = 0, the derivative is undefined. The quantity (f'g - fg') must be 0 to satisfy the equation.
 
SteamKing said:
If g^2 = 0, the derivative is undefined. The quantity (f'g - fg') must be 0 to satisfy the equation.
To elaborate on what SteamKing said, the basic idea is that if a/b = 0, then a = 0. Of course, b cannot be 0.
 
Thanks everyone!
 

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