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R^2 = 8/(2-sin^2 θ) Convert to rectangular form?

  1. Oct 2, 2011 #1
    Is it right to multiply everything on both sides first, by the (2-sin^2 θ) ? Why would you want to do that? In terms of how it should look, and what variable to solve for, what exactly is the goal here and why?
     
  2. jcsd
  3. Oct 2, 2011 #2

    vela

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    Yes, you can do that. When converting to rectangular form, you want to get each sine and cosine multiplied by R because x=R cos θ and y=R sin θ. (I'm assuming you're working with polar coordinates here.) Here you have sin2 θ, so you want it multiplied by R2, one factor of R for each sine.
     
    Last edited: Oct 2, 2011
  4. Oct 2, 2011 #3

    eumyang

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    You don't necessarily solve for a variable. The goal is to rewrite the equation so that the variables are x's and y's, not r's and θ's. After multiplying both sides by the denominator, add sin2 θ to both sides, and then use the equations that vela gave you. (They are the same one's I mentioned in your previous thread.)
     
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