- #1
pat666
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R circuit (pretty simple) need checked - full working - please!
see attachment
P=IV
P_loss=I^2 R
V=IR
ok
36=I^2*12
I_12Ω=√3 A
V=20.8V
That is the same for the 3 resistors in parallel (I hope)
so I18Ω=1.15A
I36Ω=0.577A
the sum of these will give me the current through the unknown resistor
Iunknown=3.46A
net voltage = 60
60=Vunknown + 20.8
Vunknown=39.2V
V=IR
R=11.3Ω
can someone please check this - wouldn't ask if I dint need it.
Homework Statement
see attachment
Homework Equations
P=IV
P_loss=I^2 R
V=IR
The Attempt at a Solution
ok
36=I^2*12
I_12Ω=√3 A
V=20.8V
That is the same for the 3 resistors in parallel (I hope)
so I18Ω=1.15A
I36Ω=0.577A
the sum of these will give me the current through the unknown resistor
Iunknown=3.46A
net voltage = 60
60=Vunknown + 20.8
Vunknown=39.2V
V=IR
R=11.3Ω
can someone please check this - wouldn't ask if I dint need it.