A person is standing outdoors in the shade where the temperature is 27°C.
(a) What is the radiant energy absorbed per second by his head when it is covered with hair? The surface area of the hair (assumed to be flat) is 160 cm2 and its emissivity is 0.85.
(b) What would be the radiant energy absorbed per second by the same person if he were bald and the emissivity of his head were 0.66?
e = .85 for a, .66 for b
sigma = 5.67*10^-8
A = 1.6m squared
T = 300.15K (27 + 273.15)
q = e*sigma*T^4*A*t
The Attempt at a Solution
By plugging in the known variables, I got
Q/(1 sec) = .85*(5.67x10^-8)*((300.15) ^4)*1.6m squared
Q =625.86 J/s
Q/(1 sec) = .66*(5.67x10^-8)*((300.15) ^4)*1.6m squared
Q = 485.96 J/s
I was told by webassign these answers were wrong. Am I not solving just for Q here? I can't think of any other way besides solving for Q. Also, I'm not sure on the temperature. Do I just take the 27 and convert to kelvin or do I have to do something else? thanks in advance for the help