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Radiationless de-excitation - how does radiative heating work?

  1. Aug 26, 2014 #1
    You typically hear of radiative heating as exciting an electron to a higher state in an atom or molecule, but heat energy is the excessive vibration of a molecule. How do you reconcile these two models? I've heard of something called radiationless de-excitation whereby the electron passes its energy to the molecule and becomes de-excited. Is this the correct way to think about standard radiative heating?
     
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  3. Aug 27, 2014 #2

    Andy Resnick

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    If I understand you correctly, you are asking about photon-phonon coupling as a description of optical absorption and heating. I'm not an expert on this, but many solid-state and radiation heat transfer books give an account.
     
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