Radiationless de-excitation - how does radiative heating work?

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SUMMARY

Radiative heating involves the excitation of electrons to higher energy states, but it is fundamentally linked to the vibrational energy of molecules. Radiationless de-excitation is a key concept where excited electrons transfer their energy to the surrounding molecular vibrations, leading to thermal energy increase. This process is effectively described by photon-phonon coupling, which is crucial for understanding optical absorption and subsequent heating in materials. Solid-state physics and radiation heat transfer literature provide comprehensive insights into these mechanisms.

PREREQUISITES
  • Understanding of electron excitation and de-excitation processes
  • Familiarity with molecular vibrations and thermal energy concepts
  • Knowledge of photon-phonon coupling mechanisms
  • Basic principles of solid-state physics and radiation heat transfer
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  • Research photon-phonon coupling in detail
  • Study the principles of optical absorption in materials
  • Explore solid-state physics textbooks for advanced concepts
  • Investigate radiation heat transfer mechanisms in various materials
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Physicists, materials scientists, and engineers interested in the mechanisms of radiative heating and energy transfer in solid-state systems.

questing4truth
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You typically hear of radiative heating as exciting an electron to a higher state in an atom or molecule, but heat energy is the excessive vibration of a molecule. How do you reconcile these two models? I've heard of something called radiationless de-excitation whereby the electron passes its energy to the molecule and becomes de-excited. Is this the correct way to think about standard radiative heating?
 
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If I understand you correctly, you are asking about photon-phonon coupling as a description of optical absorption and heating. I'm not an expert on this, but many solid-state and radiation heat transfer books give an account.
 

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