Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Radiationless de-excitation - how does radiative heating work?

  1. Aug 26, 2014 #1
    You typically hear of radiative heating as exciting an electron to a higher state in an atom or molecule, but heat energy is the excessive vibration of a molecule. How do you reconcile these two models? I've heard of something called radiationless de-excitation whereby the electron passes its energy to the molecule and becomes de-excited. Is this the correct way to think about standard radiative heating?
     
  2. jcsd
  3. Aug 27, 2014 #2

    Andy Resnick

    User Avatar
    Science Advisor
    Education Advisor
    2016 Award

    If I understand you correctly, you are asking about photon-phonon coupling as a description of optical absorption and heating. I'm not an expert on this, but many solid-state and radiation heat transfer books give an account.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Radiationless de-excitation - how does radiative heating work?
  1. Radiation + Heat (Replies: 3)

  2. Radiating Heat (Replies: 3)

Loading...