Radioactive Decay: A Problem in Differential Equations

Click For Summary
The discussion revolves around solving a differential equation for the radioactive decay of Bismuth and Lead, derived from Uranium. The user has formulated a differential equation for Lead and derived its solution, but seeks confirmation on the correctness of their equation for Bismuth, which incorporates the decay of Lead. There is a debate about the necessity of knowing the initial amount of Uranium to determine the quantities of Lead and Bismuth produced, with clarification that the focus is on the decay of the latter two isotopes. The user is looking for assistance in solving for the constants in their Bismuth equation based on the initial value problem. The conversation highlights the complexities of modeling radioactive decay in differential equations.
Bachelier
Messages
375
Reaction score
0
I've been working with this problem for almost two weeks trying to find a good equation for the decay of Bismuth to no avail.

Can someone give me insightful comments:

Here's the problem:


Homework Statement



In the radioactive decay series of Uranium (238, 92), isotopes of lead, bismuth occur as products of two successive Beta decays with half -lives of 19.7 minutes and 26.8 minutes, respectively.

U --> Lead --> Bismuth

Decays are each proportional to the amount of isotope present.
Assume initially at time =0, we have 100 mg of lead and 150 mg of bismuth?

We are asked to find the amount of lead and bismuth at any time?

Homework Equations



So first we have to formulate a DE for the decay.

The one equation for Lead is simple.

Let L(t) be the amount of lead at any time, then the DE model is:

dL/dt = -a.L​
(a: constant of decay)

after integration and get L(t) = 100.e^(-a.t)

Using the Initial Value Problem and half-life value we get an equation:
L(t)= 100.e^(-.035185.t)

Now the Differential Equation for Bismuth is: (B(t): the amount of Bismuth at any time)

dB/dt= -b.B + a.L​
(a.L: quantity of lead decayed added to the Bismuth which equals 100.e^(-.035185.t)) and b: constant of decay for Bismuth

Solving this 1st Order DE we get:

[100.e^(-.035185.t) + C.100.e^(-b.t)]​
B(t)= _____________________________________
[b -.035]​


C is a constant of integration.

First: Is my B(t) equation correct based on the problem we have?

And second, how can I solve for b and C based on the IVP I have?

Can you guys help?

thx :)
 
Physics news on Phys.org
shouldn't we need to know how much uranium there is to know how much lead is created from the decay of uranium? i don't think there is loss of mass in beta decay, so the conversion is 1:1.
 
xaos said:
shouldn't we need to know how much uranium there is to know how much lead is created from the decay of uranium? i don't think there is loss of mass in beta decay, so the conversion is 1:1.

Actually what we are studying here is the decay of both Lead and Bismuth.

The Uranium is mentioned here to give an idea that both isotopes are derived from Ur. :)
 
O Come on guys, is this such a difficult problem?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
4
Views
5K
Replies
2
Views
1K