Radius of a curvature for specific force on a seat in a jet

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SUMMARY

The minimum radius of curvature for a jet pulling out of a vertical dive at a speed \( v \), where the force on the pilot's seat is 7 times his weight, is calculated using the formula \( r = \frac{v^2}{6g} \). This conclusion arises from the understanding that the normal force acting on the seat is 7 mg, with the pilot's weight contributing an additional mg, leading to a net force of 6 mg responsible for the centripetal acceleration. The discussion clarifies that the 7 mg force is indeed the normal force and not just an additional force acting on the seat.

PREREQUISITES
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  • Familiarity with centripetal force calculations
  • Knowledge of forces acting on objects in circular motion
  • Basic algebra for manipulating equations
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54stickers
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The question is:

What is the minimum radius of curvature of a jet, pulling out of a vertical dive at a speed of v, if the force on the pilot's seat is 7 times his weight?



The way I thought to answer this is just to say that, 7 mg, the net force on the seat will be equal to the angular acceleration. This does not assume that the 7mg force is just a normal force on the seat, but the Normal added to mg is a total of 7mg. Leaving a normal of 8mg

so that

7mg = (mv^2)/r

then

r = (v^2)/ 7g

The answer to the question according to the answer sheet is that 7 mg is going to be the normal force, and that the angular acceleration that creates a 7 mg normal force is going to be that of 6mg so:

N - mg = (mv^2)/r

7mg - mg = (mv^2)/r

then

r = (v^2)/6g

My question is which one is correct?
based on the wording of the question I don't think that it is okay to assume that the 7 mg is a only a normal. Am I okay to say this?

Thanks!
 
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54stickers said:
My question is which one is correct?
based on the wording of the question I don't think that it is okay to assume that the 7 mg is a only a normal. Am I okay to say this?
The answer sheet is correct. The force on the seat is the normal force. (The weight of the pilot acts on the pilot, not the seat.)
 

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