Radius of Convergence for Moderately Complicated Series

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
4 replies · 2K views
LukeMiller86
Messages
5
Reaction score
0
1. The problem statement:

Show that the following series has a radius of convergence equal to [tex]exp\left(-p\right)[/tex]

Homework Equations



For p real:

[tex]\Sigma^{n=\infty}_{n=1}\left( \frac{n+p}{n}\right)^{n^{2}} z^{n}[/tex]

The Attempt at a Solution


[tex]\stackrel{lim}{n\rightarrow\infty}\left|a_{n}\right|^{1/n} = \frac{1}{R} = \left(\frac{n+p}{n}\right)^{n}<br /> =exp\left(n\left(ln\left(\frac{n+p}{n}\right)\right)\right)[/tex]

Apart from playing with the logarithm after that I cannot seem to reach the required answer.
Any help would be greatly appreciated.
 
Physics news on Phys.org
What's the limit definition of the exponential function?
 
[tex]exp\left(-p\right) = e^{\left(-p)\right}[/tex]

is that what you meant?
 
Do you know this limit:
[tex]\lim_{n\to\infty}\left(1+\frac{p}{n}\right)^n[/tex]
 
Completely overlooked that! Thanks very much.