Radius of motion of particle through magnetic field.

1. Mar 15, 2007

KingNothing

I know that $$$R = \frac{{mv}}{{\left| q \right|B}}$$$, but I am unsure how to calculate the velocity, and I certainly don't know how to calculate the charge. My educated guess is that velocity and charge are directly proportional over a potential difference so that they don't matter in this problem, but I don't have any equations relating the three.

Last edited: Mar 15, 2007
2. Mar 16, 2007

Mentz114

'Singly charged' means having the charge of one electron. So you do know the charge and now can calculate the velocity generated by the voltage drop.

3. Mar 16, 2007

Astronuc

Staff Emeritus
Well, in the case of an atom, or more precisely, ion, singly charged usually means a single + charge (i.e. it has one less electron than the neutral atom).

The velocity can be determined from the kinetic energy, which is equal to the energy received from being accelerated (assume from rest) across a potential difference (229 V). One unit charge 'q' or 'e' is receives 1 eV of energy from a 1 V potential.