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Radius of motion of particle through magnetic field.

  1. Mar 15, 2007 #1
    I know that [tex]\[
    R = \frac{{mv}}{{\left| q \right|B}}
    \][/tex], but I am unsure how to calculate the velocity, and I certainly don't know how to calculate the charge. My educated guess is that velocity and charge are directly proportional over a potential difference so that they don't matter in this problem, but I don't have any equations relating the three.
     
    Last edited: Mar 15, 2007
  2. jcsd
  3. Mar 16, 2007 #2

    Mentz114

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    Gold Member

    'Singly charged' means having the charge of one electron. So you do know the charge and now can calculate the velocity generated by the voltage drop.
     
  4. Mar 16, 2007 #3

    Astronuc

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    Staff: Mentor

    Well, in the case of an atom, or more precisely, ion, singly charged usually means a single + charge (i.e. it has one less electron than the neutral atom).

    The velocity can be determined from the kinetic energy, which is equal to the energy received from being accelerated (assume from rest) across a potential difference (229 V). One unit charge 'q' or 'e' is receives 1 eV of energy from a 1 V potential.
     
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