Ramp Problem, Friction, Find Theta

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SUMMARY

The discussion focuses on solving a physics problem involving two blocks of masses 2m and m connected by a weightless string over a frictionless pulley. The goal is to determine the incline angle θ that allows the blocks to move at a constant speed, considering the coefficient of kinetic friction μ and gravitational force g. The equations derived include 2mg sin(θ) - μmg cos(θ) - T = 0 for the 2m mass and T - mg = 0 for the m mass, leading to the relationship 2 sin(θ) - 2μ cos(θ) = 1. The solution requires manipulation using trigonometric identities and careful attention to signs in the equations.

PREREQUISITES
  • Understanding of Newton's second law, specifically the equation F = ma.
  • Familiarity with trigonometric identities, particularly secant and tangent functions.
  • Knowledge of kinetic friction and its role in motion on inclined planes.
  • Basic principles of pulley systems in classical mechanics.
NEXT STEPS
  • Study the derivation of forces in pulley systems using free-body diagrams.
  • Learn about the application of trigonometric identities in physics problems.
  • Explore the effects of varying coefficients of friction on motion along inclined planes.
  • Investigate the implications of constant speed motion in dynamic systems.
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Students of physics, particularly those studying mechanics, educators teaching classical mechanics concepts, and anyone interested in solving complex problems involving forces, motion, and friction.

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Challenging Ramp and Pulley Problem

Homework Statement



Two blocks of masses 2m and m are connected by a weightless string over a frictionless, massless pulley, as shown in the figure. The coefficient of kinetic friction between the block and the incline is \mu. The system is in a uniform gravitational field directed downward of strength g. Find the incline angle \theta such that the blocks move at a constant speed. Distinguish between the cases of upward and downward motion. Rationalize your solutions using a simple physical picture.

Homework Equations


\mathbf{F} = m\mathbf{a}

The Attempt at a Solution



So we start by looking at the forces acting on each block. In this case, we will be looking at downward motion. For the 2m mass:
2mg\sin\theta - \mu mg\cos\theta - T = 0
And for the second block:
T - mg = 0 \implies T = mg
Using the second equation and plugging into the first equation, we find:
2\sin\theta - 2\mu\cos\theta = 1
I can't figure out how to solve for \theta. Wolfram's answer is pretty ugly.
 

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You need trig identities and a bit of manipulation:

Divide through by ##\cos(\theta)##
##1/\cos(\theta)=\sec(\theta)##

Square both sides and expand the RHS
##\sec^2(\theta)=1+\tan^2(\theta)##

Change variables: ##x=\tan(\theta)##
Look familiar?

Note - you have misplaced a minus sign in the first equation.
gravity and friction both point in the opposite direction to tension.
 

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