Range in Linear Transformation

Click For Summary
SUMMARY

The discussion focuses on the concept of the range in linear transformations, specifically for the transformation L: R^3 -> R^2 defined as L(x) = (0,0)^T. It concludes that the basis for this range is the empty set, resulting in a dimension of zero. Additionally, for the transformation L(x) = (x2, x3)^T, the basis is identified as {(1,0)^T, (0,1)^T}, indicating that the range spans all of R^2. The relationship between rank and nullity is also referenced through the equation Rank(A) - Nullity(A) = n.

PREREQUISITES
  • Understanding of linear transformations and vector spaces
  • Familiarity with the concepts of basis and dimension in linear algebra
  • Knowledge of the Rank-Nullity Theorem
  • Proficiency in working with R^n spaces
NEXT STEPS
  • Study the Rank-Nullity Theorem in detail
  • Explore examples of linear transformations in R^n
  • Learn about the concept of span and linear independence
  • Investigate the implications of different bases on vector space dimensions
USEFUL FOR

Students and educators in linear algebra, mathematicians focusing on vector spaces, and anyone seeking to deepen their understanding of linear transformations and their properties.

mrshappy0
Messages
97
Reaction score
0

Homework Statement


L: R^3 -> R^2
L(x)=(0,0)^T
What is the basis, and dim of the Range?


Homework Equations


Rank(A)-Nullity(A)=n


The Attempt at a Solution


So clearly L(x)= (0,0)^T. So the basis must be the empty space and dim is zero, right?

Now, going of this same logic, Say L(x)=(x2,x3)^T. The basis would be {(1,0)^T, (0,1)^T} does this mean the range is just the Span of these two linearly independent vectors--> Span (v1,v2)?
 
Physics news on Phys.org
mrshappy0 said:

Homework Statement


L: R^3 -> R^2
L(x)=(0,0)^T
What is the basis, and dim of the Range?


Homework Equations


Rank(A)-Nullity(A)=n


The Attempt at a Solution


So clearly L(x)= (0,0)^T. So the basis must be the empty space and dim is zero, right?
Every vector space must consist of at least the zero vector, so a basis for the range of L would be <0, 0>. The dimension of the range is zero, which is what you said.
mrshappy0 said:
Now, going of this same logic, Say L(x)=(x2,x3)^T. The basis would be {(1,0)^T, (0,1)^T} does this mean the range is just the Span of these two linearly independent vectors--> Span (v1,v2)?
That's what a basis is - a set of vectors that spans some space or subspace. In this example, the range is all of R2.
 
#44, for the win. Thanks you.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
15
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
34
Views
4K
Replies
26
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K