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Homework Help: Range of wavelength from white light through a diffraction grating

  1. Mar 24, 2010 #1
    1. The problem statement, all variables and given/known data

    A narrow beam of collimated white light falls at normal incidence upon a transmission grating with 3150 lines per cm. A spectrum is formed by the grating on a screen 30 cm away. If a 1 cm square hole is cut in the screen its inner edge being 5 cm from the zeroth order, what range of visible wavelengths passes through the hole?

    2. Relevant equations

    N[tex]\lambda[/tex] = dsin[tex]\theta[/tex]

    3. The attempt at a solution

    [tex]\frac{\Delta\lambda}{\theta\Delta}[/tex] = [tex]\frac{d}{N}[/tex][tex]\sqrt{1 - sin^2\theta}[/tex]
  2. jcsd
  3. Mar 25, 2010 #2


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    What is the range of angle determined by the square hole ?

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