Range of wavelength from white light through a diffraction grating

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Homework Statement



A narrow beam of collimated white light falls at normal incidence upon a transmission grating with 3150 lines per cm. A spectrum is formed by the grating on a screen 30 cm away. If a 1 cm square hole is cut in the screen its inner edge being 5 cm from the zeroth order, what range of visible wavelengths passes through the hole?

Homework Equations



N[tex]\lambda[/tex] = dsin[tex]\theta[/tex]

The Attempt at a Solution



[tex]\frac{\Delta\lambda}{\theta\Delta}[/tex] = [tex]\frac{d}{N}[/tex][tex]\sqrt{1 - sin^2\theta}[/tex]
 

Answers and Replies

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ehild
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What is the range of angle determined by the square hole ?

ehild
 

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