Rank 3 tensor created by taking the derivative of electromagnetic field tensor

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SUMMARY

The discussion focuses on demonstrating that the rank 3 tensor Sαβγ = Fαβ,γ + Fβγ,α + Fγα,β is completely antisymmetric. Participants clarify that for Sαβγ to be antisymmetric, it must satisfy the conditions Sαβγ = -Sαγβ, Sαβγ = -Sβαγ, and Sαβγ = -Sγβα. Additionally, if Sαβγ equals zero, it indicates that the tensor has no antisymmetric components.

PREREQUISITES
  • Understanding of tensor calculus
  • Familiarity with electromagnetic field tensors
  • Knowledge of antisymmetry properties in tensors
  • Basic concepts of differential notation
NEXT STEPS
  • Study the properties of rank 3 tensors in detail
  • Explore the implications of antisymmetry in physical applications
  • Learn about the electromagnetic field tensor Fαβ and its derivatives
  • Investigate examples of completely antisymmetric tensors in physics
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Students and researchers in theoretical physics, particularly those studying electromagnetism and tensor analysis, will benefit from this discussion.

mjordan2nd
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Homework Statement



Show that the rank 3 tensor S_{\alpha \beta \gamma}=F_{\alpha \beta , \gamma} + F_{\beta \gamma , \alpha} + F_{\gamma \alpha , \beta} is completely antisymmetric.

I just don't feel comfortable doing this stuff at all. Each of the three terms seems like they should be exactly the same to me. Could someone show me how I would start doing something like this please? Furthermore, if this is a rank 3 tensor, what would it mean if this tensor equals 0?

Thanks. :-\
 
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If S_{\alpha\beta\gamma} is completely antisymmetric, then

S_{\alpha\beta\gamma}=-S_{\alpha\gamma\beta}
S_{\alpha\beta\gamma}=-S_{\beta\alpha\gamma}

and

S_{\alpha\beta\gamma}=-S_{\gamma\beta\alpha}

That is, S_{\alpha\beta\gamma} is antisymmetric on all pairs of indices...

So, start by comparing S_{\alpha\beta\gamma} to S_{\alpha\gamma\beta} using the definition you posted...
 

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