- #1

stunner5000pt

- 1,461

- 2

ok so the volume of a prism is

[tex] V = \frac{1}{2} lwh [/tex] ... (1)

l is the length

w is the width

h is the height

now dl/dt = 0 because the length of the column of water is constant

to find a relation between h and w i got this because the triangle is an equilaterla triangle

[tex] h = \frac{\sqrt{3}}{2} w[/tex] ... (2)

and it follos that

[tex] \frac{dh}{dt} = \frac{\sqrt{3}}{2}\frac{dx}{dt} [/tex] ... (3)

now subbing 1 into 2

[tex] V = \frac{1}{\sqrt{3}} lh^2 [/tex]

[tex] \frac{dV}{dt} = \frac{l}{\sqrt{3}} 2h \frac{dh}{dt} [/tex]

now here's the problem ... what is h??

h does not represent the depth of the water, does it??

it reprsnts the height of the remainder of the prism that has not been filled iwht water. so really

[tex] \frac{dh_{water}}{dt} = \frac{dh_{empty part}}{dt} [/tex]

is it reasonable to say that??

thank you for all your input!